Chuong Nguyen U84536721 Post Lab Report Experiment 6 cope out B ( deoxycytidine monophosphate points) 1. (15 points) Prepare a table list the caboodle of the starting materials used and the trade of the dried proceeds you collected. mastermind the percent supply for each compound. soften 1| | Part 2| | Material| occur| Material| Amount| KMnO4| 3.7580 g| [NiCl2(PPh3)2]| 0.6026 g| C5H8O2| 16.6 g| NH4SCN| 0.8024 g| Product| | PPh3| 2.0016 g| Mn(acac)3| 6.119 g| Product| | | | [Ni(NCS)2(PPh3)2]| 1.56 g| % show= mass of convergence/ mass of reactant x 100% Part I 4 KMnO4 + 12 C5H8O2 4 Mn(C5H8O2)3 + 2 K2O + 7 O2 Theoretical yield 0.027 bulwark KMnO4 x 352.26 g/mol Mn(C5H8O2)3 (1:1 ratio) = 9.51 g Mn(C5H8O2)3 0.166 mol C5H8O2 x 352.26 g/mol Mn(C5H8O2)3 (3:1 ratio) = 19.47 g Mn(C5H8O2)3 Limiting reactant KMnO4 Mn(acac)3 %yield = 6.110 g /9.51 g KMnO4 x 100% = 64.25% Part II [NiCl2(PPh3)2] + 2NH4SCN [Ni(NCS)2(PPh3)2] + 2 NH4Cl Theoretical yield .6026 g /259. 54g/mol[NiCl2(PPh3)2] x 304.80 g/mol [Ni(NCS)2(PPh3)2] (1:1 ratio) = 0.7076 g [Ni(NCS)2(PPh3)2] 0.8024 g/ 76.122g/mol NH4SCN x 304.80 g/mol [Ni(NCS)2(PPh3)2] (2:1 ratio) = 1.606 g Limiting reactant [NiCl2(PPh3)2] [Ni(NCS)2(PPh3)2] % yield = 1.56g / 0.7076 g x 100% = 220.

46 % (Excess triphenylphosphine need to account in chemical reply and product yield) 2. (15 points): Prepare a table listing both the observational magnetic data you obtained for the three compounds you measured. From the data you accumulated, account the grand force ?g of your samples. Convert your gram susceptibility to torpedo susceptibility, ?M. Compound| L| W| Ro| R| Mn(acac)3| 3.0 cm| 0.1744 g| -32| 1714| [NiCl2(PPh3)2]| 3.2 cm| 0.1333g| -32|! 220| [Ni(NCS)2(PPh3)2]| 4.0 cm| 0.1414 g| -32| -56| ?g = 1.007 (L)(R-R0)/(109)(m) Mn(acac)3= 1.007(3)(1714- (-32)/ (0.1744 x 109) = 3.024 x10-5 [NiCl2(PPh3)2] = 1.007(3.2)(220 (-32)/ (0.1333 x 109) = 6.091 x 10-6 [Ni(NCS)2(PPh3)2] = 1.007(4)(-56 (-32)/ (0.1414 x...If you want to get a in effect(p) essay, army it on our website:
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